A bag has $4$ red, $6$ blue and $5$ green balls. A ball is drawn at random. Probability that it is blue is:

A bag has $4$ red, $6$ blue and $5$ green balls. A ball is drawn at random. Probability that it is blue is:
  1. $\dfrac{4}{15}$
  2. $\dfrac{1}{3}$
  3. $\dfrac{2}{5}$
  4. $\dfrac{1}{2}$

Solution

Total $= 4+6+5 = 15$. $P(\text{blue}) = \dfrac{6}{15} = \dfrac{2}{5}$.

Asked in: IMO

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