A bag contains $n$ white and $n$ black balls. Pairs of balls are drawn at random without replacement…

A bag contains $n$ white and $n$ black balls. Pairs of balls are drawn at random without replacement successively, until the bag is empty. If the number of ways in which each pair consists of one white and one black ball is 14400 , then $n$ is equal to
  1. 6
  2. 5
  3. 4
  4. 3

Solution

According to the given condition $\left({ }^n C_1{ }^n C_1\right)\left({ }^{n-1} C_1{ }^{n-1} C_1\right) \ldots\left({ }^1 C_1^1 C_1\right)=14400$ $\begin{aligned} & \Rightarrow \quad\left({ }^n C^{n-1} C_1 \ldots{ }^1 C_1\right)^2=(120)^2 \\ & \Rightarrow \quad n(n-1)(n-2) \ldots 1=120 \\ & \Rightarrow \quad n !=5 \text { ! } \\ & \Rightarrow \quad n=5 \\ & \end{aligned}$

Asked in: AP EAMCET 2011

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