A bag contains $5$ red and $3$ green balls. A ball is drawn at random. Probability of getting a red ball is:

A bag contains $5$ red and $3$ green balls. A ball is drawn at random. Probability of getting a red ball is:
  1. $\dfrac{3}{8}$
  2. $\dfrac{5}{8}$
  3. $\dfrac{1}{2}$
  4. $\dfrac{5}{3}$

Solution

Total $= 5+3 = 8$. Favourable $= 5$ red. $P(\text{red}) = \dfrac{5}{8}$.

Asked in: IMO

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