A bag contains $20$ tickets numbered $1$-$20$. Probability of drawing a ticket whose number is divisible by…

A bag contains $20$ tickets numbered $1$-$20$. Probability of drawing a ticket whose number is divisible by $5$ is
  1. $\dfrac{1}{5}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{1}{20}$
  4. $\dfrac{4}{20}$

Solution

Multiples of $5$: $5, 10, 15, 20$ — $4$ favourable. $\dfrac{4}{20} = \dfrac{1}{5}$.

Asked in: MH-SSC-9

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