A bag contains 3 white, 2 blue and 5 red balls. One ball is drawn at random from this bag. Then, the…

A bag contains 3 white, 2 blue and 5 red balls. One ball is drawn at random from this bag. Then, the probability that the ball drawn is not red is
  1. $3 / 10$
  2. $1 / 5$
  3. $1 / 2$
  4. $4 / 5$

Solution

3 white, 2 blue, 5 red balls. $ P(\text { ball is not red })=\frac{3+2}{3+2+5}=\frac{1}{2} $

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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