A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. Then, the probability that none of the balls drawn is blue is

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Aicharya · Accepted Answer

Given bag contains 2 red, 3 green 2 blue balls $ \begin{aligned} & \mathrm{P} 	ext { (none ball drawn is blue) }=\frac{{ }^2 \mathrm{c}_2+{ }^3 \mathrm{c}_2+{ }^2 \mathrm{c}_1+{ }^3 \mathrm{c}_1}{{ }^7 \mathrm{c}_2} \ & =\frac{1+3+2 	imes 3}{\frac{7 	imes 6}{2}}=\frac{4+6}{7 	imes 3}=\frac{10}{21} \end{aligned} $

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. Then, the probability that…

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