A bag consists of 3 red balls, 5 blue balls and 8 green balls. A ball is selected at random. What is the…

A bag consists of 3 red balls, 5 blue balls and 8 green balls. A ball is selected at random. What is the probability of not getting a blue ball?
  1. \(\frac{11}{16}\)
  2. \(\frac{3}{16}\)
  3. \(\frac{1}{2}\)
  4. \(\frac{5}{16}\)

Solution

\(P(B)=\frac{5}{16} \Rightarrow P(\bar{B})=\frac{11}{16}\)

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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