A 800 turn coil of the effective area 0.05 m 2 is kept perpendicular to the magnetic field 5 × 10 - 5 T . When the plane of the coil is rotated by 90 o around any of its coplanar axis in 0.1 s , the emf induced in the coil will be:

Question

Aicharya · Accepted Answer

By Faraday's law, induced EMF in coil is equal to rate of change of magnetic flux linked with coil so

$ε = - \frac{∆ ϕ}{∆ t}$ $= - \frac{ϕ_{f} - ϕ_{i}}{∆ t}$ $= - \frac{0 - N B A}{∆ t}$
$= \frac{800 \times 5 \times 10^{- 5} \times 0.05}{0.1}$
$= 0.02 V$

A 800 turn coil of the effective area 0.05 m 2 is kept perpendicular to the magnetic field 5 × 10 - 5 T .…

Solution