A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside…
(Given : density of water $=1000 \mathrm{~kg} \mathrm{~m}^{-3}$)
- $1400 \mathrm{~cm}^3$
- $600 \mathrm{~cm}^3$
- $4000 \mathrm{~cm}^3$
- $400 \mathrm{~cm}^3$
Solution
$\begin{aligned}
& =\left(\frac{\text { Density of cube }}{\text { Density of water }}\right) \times \text { Volume of cube } \\ & =\frac{\text { Mass of cube }}{\text { Density of water }} \\ & =\frac{400 \mathrm{gm}}{1 \mathrm{gm} / \mathrm{cm}^3} \\ & =400 \mathrm{~cm}^3
\end{aligned}$
Volume of cube outside water
$\begin{aligned}
& =\text { Volume of cube }- \text { Volume of cube inside water } \\ & =1000 \mathrm{~cm}^3-400 \mathrm{~cm}^3 \\ & =600 \mathrm{~cm}^3
\end{aligned}$
Asked in: JEE Main 2025 (28 Jan Shift 2)
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