A 30   kg slab B rests on a frictionless floor as shown in the figure. A 10   kg block A rests on…

A 30 kg slab B rests on a frictionless floor as shown in the figure. A 10 kg block A rests on top of the slab- B. The coefficients of static and kinetic friction between the block A and the slab B are 0.60 and 0.40 respectively. When block-A is acted upon by a horizontal force of 100 N, as shown, find the resulting acceleration of the slab- B. g=9.8 m s-2

  1. 0.98 m s-2
  2. 1.47 m s-2
  3. 1.52 m s-2
  4. 1.31 m s-2

Solution

The maximum frictional force, μsN=0.6×10×9.8=58 N

As the frictional force is less than the applied force, the block and slab won't move together.

For the block, f=μmg=0.4×10×0.98

⇒f=39.2 N

The slab moves due to the kinetic friction.

Resulting acceleration of the slab, a=fM=39.230=1.31 m s-2

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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