A \(200 \mathrm{~W}, 100 \mathrm{~V}\) bulb is connected in series with an electrolytic cell. If an aqueous…

A \(200 \mathrm{~W}, 100 \mathrm{~V}\) bulb is connected in series with an electrolytic cell. If an aqueous solution of an Sn-salt is electrolysed for \(5 \mathrm{hrs}\), \(11.1 \mathrm{~g}\) of \(\mathrm{Sn}\) gets deposited. The chemical formula of the compound is (Given atomic weight of \(\mathrm{Sn}\) is \(118.7 \mathrm{~g} \mathrm{~mol}^{-1}\)).
  1. \(\mathrm{SnO}\)
  2. \(\mathrm{SnCl}_2\)
  3. \(\mathrm{SnCl}_4\)
  4. \(\mathrm{SnO}_2\)

Solution

\(\therefore w=\frac{E i t}{F}=\frac{\frac{A}{n} \times i \times t}{F}\) \(\Rightarrow \quad n=\frac{A \times i \times t}{w \times F}=\frac{118.7 \times 2 \times(5 \times 3600)}{11.1 \times 96500}=3.989\) \(A=\) atomic weight of \(\mathrm{Sn}=118.7 \mathrm{~g} \mathrm{~mol}^{-1}\) \(i=\text { current }=\frac{200 \mathrm{~W}}{100 \mathrm{~V}}=2 \mathrm{~A}\) \(t=\text { time }=5 \mathrm{hrs}(5 \times 3600 \mathrm{~s})\) \(E=\frac{A}{n}=\) equavalent weight of \(\mathrm{Sn}^{n+}\) \(n=\) valency of \(\mathrm{Sn}\) in the salt \(w=\) mass of \(\mathrm{Sn}\) deposited \(=11.1 \mathrm{~g}\) Here, \(\mathrm{SnO}\) and \(\mathrm{SnO}_2\) are non-electrolytes (aqueous). So, valency of \(\mathrm{Sn}\) will be 4 in \(\mathrm{SnCl}_4\left(\mathrm{Sn}^{4+}+4 \mathrm{Cl}^{-}\right)\).

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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