A 16   Ω wire is bent to form a square loop. A 9   V supply having an internal resistance of 1   Ω is connected across one of its sides. The potential drop across the diagonals of the square loop is __________ × 10 - 1   V .

Question

A 16 &#160; &#937; wire is bent to form a square loop. A 9 &#160; V supply having an internal resistance of 1 &#160; &#937; is connected across one of its sides. The potential drop across the diagonals of the square loop is __________ &#215; 10 - 1 &#160; V .

Aicharya · Accepted Answer

Here assume current as By KVL in the outer loop 9 - 12 i - 4 i = 0 16 i = 9 8 i = 9 2 = 4 . 5 = 45 &#215; 10 - 1

A 16   Ω wire is bent to form a square loop. A 9   V supply having an internal resistance of…

Solution

A 16 &#160; &#937; wire is bent to form a square loop. A 9 &#160; V supply having an internal resistance of…

Solution

A 16 Ω wire is bent to form a square loop. A 9 V supply having an internal resistance of…