$9.3 \mathrm{~g}$ of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100\% yield/conversion) is _______ g. (nearest integer)

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Aicharya · Accepted Answer

Reaction suggests that 1 mole of aniline give 1 mole of orange dye. $\begin{aligned} & \text { so }(\mathrm{mol})_{\text {aniline }}=(\mathrm{mole})_{\text {orange dye }} \\ & \frac{9.3 \mathrm{~g}}{93 \mathrm{~g} \mathrm{~mol}^{-1}}=\frac{\text { mass of orange dye }}{199 \mathrm{~g} \mathrm{~mol}^{-1}} \end{aligned}$ mass of orange dye $=19.9 \mathrm{~g} \simeq 20 \mathrm{~g}$

\(9.3 \mathrm{~g}\) of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye.…

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