90 J of work is done to move an electric charge of magnitude 3 C from a place A , where potential is -10 V…

90 J of work is done to move an electric charge of magnitude 3 C from a place A , where potential is -10 V to another place B , where potential is ' $\mathrm{V}_1$ ' volt. The value of $\mathrm{V}_1$ is
  1. 10 V
  2. 20 V
  3. 30 V
  4. -40 V

Solution

$\begin{aligned} & \mathrm{W}=\mathrm{q} \Delta \mathrm{~V} \\ & \mathrm{~W}=\mathrm{q}\left(\mathrm{~V}_1-\mathrm{V}_{\mathrm{A}}\right) \\ & \mathrm{W}=3\left[\mathrm{~V}_1-(-10)\right] \\ & \frac{90}{3}=\mathrm{V}_1+10 \\ & \mathrm{~V}_1=20 \mathrm{~V} \end{aligned}$

Asked in: MHT CET 2024 (02 May Shift 1)

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