9 moles of "D" and 14 moles of $\mathrm{E}$ are allowed to react in a closed vessel according to given reactions. Calculate number of moles of B formed in the end of reaction, if 4 moles of $G$ are present in reaction vessel. (Percentage yield of reaction is mentioned in the reaction)
Step-1 $3 \mathrm{D}+4 \mathrm{E} \stackrel{80 \%}{\longrightarrow} 5 \mathrm{C}+\mathrm{A}$
Step-2 $3 \mathrm{C}+5 \mathrm{G} \stackrel{50 \%}{\longrightarrow} 6 \mathrm{~B}+\mathrm{F}$

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Aicharya · Accepted Answer

$3 \mathrm{D}+4 \mathrm{E} \stackrel{80 \%}{\longrightarrow} 5 \mathrm{C}+\mathrm{A}$
9 mole 14 mole $\frac{5}{3} \times 9 \times 0.8=12$ mole
$\underset{12 \text { mole }}{3 C}+\underset{4 \text { mole }}{5 \mathrm{G}}\stackrel{50 \%}{\longrightarrow} 6 \mathrm{~B}+\mathrm{F}$
Limiting Reagent is $\mathrm{G}$
$\therefore$ Moles of $\mathrm{B}$ formed $=\frac{6}{5} \times 4 \times 0.5=2.4$ ^

9 moles of "D" and 14 moles of $\mathrm{E}$ are allowed to react in a closed vessel according to given…

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