9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of…
9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is
- $18720$
- $18270$
- $17280$
- $12780$
Solution
Required number of arrangements
$
\begin{aligned}
& ={ }^6 P_5 \times 4 ! \\
& =720 \times 24 \\
& =17280
\end{aligned}
$
Asked in: AP EAMCET 2008
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