$\frac{\sqrt{3} \sin (\theta)+\cos (\theta)}{\sin \left(\theta+\frac{\pi}{6}\right)}=$

Question

Aicharya · Accepted Answer

$\begin{aligned} \frac{\sqrt{3} \sin \theta+\cos \theta}{\sin \left(\theta+\frac{\pi}{6}\right)} & =\frac{\sqrt{3} \sin \theta+\cos \theta}{\sin \theta \cos \frac{\pi}{6}+\cos \theta \sin \frac{\pi}{6}} \ & =\frac{\sqrt{3} \sin \theta+\cos \theta}{\frac{\sqrt{3}}{2} \sin \theta+\frac{1}{2} \cos \theta}=2 \end{aligned}$ Hence, option (c) is correct.

\(\frac{\sqrt{3} \sin (\theta)+\cos (\theta)}{\sin \left(\theta+\frac{\pi}{6}\right)}=\)

Solution