512 identical drops of mercury are charged to a potential of 2   V each. The drops are joined to form a…

512 identical drops of mercury are charged to a potential of 2 V each. The drops are joined to form a single drop. The potential of this drop is V in Volt.

Solution

Q=512 q

 Volume i= Volume f

512×43πr3=43πR3

29r3=R3

R=8 r

2=kqr

V=kQR=k512q8r

V=128 V.

Asked in: JEE Main 2021 (25 Feb Shift 1)

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