5   g   of   NaOH was dissolved in deionized water to prepare a 450   mL stock solution.…

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0.1 M solution ? Given : Molar Mass of Na, O and H is 23, 16 and 1 g mol–1 respectively

Solution

Molarity od stock solution =moles of soluteVolume of solution in L=5/400.45

M1V1=M2V2

5/400.45×V1=0.1×5001000

V1=1801000=0.18 L

 

Asked in: JEE Main 2023 (24 Jan Shift 1)

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