300   calories of heat is given to a heat engine, and it rejects 225   calories of heat. If source…

300 calories of heat is given to a heat engine, and it rejects 225 calories of heat. If source temperature is 227°C, then the temperature of sink will be _____ C.

Solution

Efficiency of Carnot engine is given by η=1-Q2Q1=1-T2T1.

1-225300=1-T2500

T2=53×225=375 K

So, temperature of sink is T2=375-273=102°C

Asked in: JEE Main 2022 (29 Jun Shift 1)

Practice more Thermodynamics questions on Aicharya