2 NO ( g ) + Cl 2 (   g ) ⇌ 2 NOCl ( s ) This reaction was studied at - 10 ° C and the…

2NO(g)+Cl2( g)2NOCl(s)
This reaction was studied at -10°C and the following data was obtained

run[NO]0Cl20   r010.100.100.1820.100.200.3530.200.201.40

[NO]0 and Cl20 are the initial concentrations and r0 is the initial reaction rate. The overall order of the reaction is
(Round off to the Nearest Integer).

Solution

r=k[NO]mCl2n

=k(0.1)m(0.1)n...1

=k(0.1)m(0.2)n.(2)

=k(0.2)m(0.2)n.(3)

n=1

m=2

m+n=3

Asked in: JEE Main 2021 (18 Mar Shift 1)

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