20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______ $ imes 10^{-2} \mathrm{M}$. (Nearest integer)

Question

20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______ $	imes 10^{-2} \mathrm{M}$. (Nearest integer)

Aicharya · Accepted Answer

$\begin{aligned} & M_F=\frac{M_1 V_1+M_2 V_2}{V_1+V_2} \ & =\frac{2 	imes 20+0.5 	imes 400}{420}=0.571 \mathrm{M} \ & =57.1 	imes 10^{-2} \mathrm{M} \ & =57\end{aligned}$

20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the…

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