2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is :
(Given : Ebullioscopic constant of water $\left.=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)$

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Aicharya · Accepted Answer

$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{i}_1 \mathrm{~m}_1 \mathrm{k}_{\mathrm{b}}+\mathrm{i}_2 \mathrm{~m}_2 \mathrm{k}_{\mathrm{b}} \ & =1 	imes \frac{2}{0.5} 	imes 0.52+\frac{1 	imes 2}{0.5} 	imes 0.52=4.16 \ & \left(\mathrm{~T}_{\mathrm{b}}ight)_{	ext {solution }}=373.16+4.16=377.3 \mathrm{~K}.\end{aligned}$

2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the…

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