2 - Methyl propyl bromide reacts with C 2 H 5 O - and gives ‘ A ’ whereas on reaction with C 2 H…

The reaction between methyl propyl bromide and ${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{O}}^{-}$ proceeds via an ${\mathrm{S}}_{\mathrm{N}}2$ (substitution nucleophilic bimolecular) mechanism. In this mechanism, the nucleophile attacks the carbon atom bearing the bromine (the electrophilic carbon) in a single step, leading to the displacement of the bromine atom.

The reaction between methyl propyl bromide and ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$ can proceed via either an ${\mathrm{S}}_{\mathrm{N}}1$ (substitution nucleophilic unimolecular). Here ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$ is a weak nucleophile. During the reaction 1,2-hydrogen shift will occur and tert-butyl ethyl ether is formed.