∫ 1 + tan x tan x + a tan x tan x + a d x =

1+tanxtanx+atanxtanx+adx=
  1. tanalogsecx+a+logsecx+C
  2. cotalogsinx-logsinx+a+C
  3. tanalogcosxsinx+a+C
  4. cotalogsinx+acosx+a+C

Solution

I=1+tanxtanx+atanxtanx+adx

We know tana=tanx+a-x=tanx+a-tanx1+tanxtanx+a

So, I=cotatanx+a-tanxtanx+atanxdx

=cota1tanx-1tanx+adx

=cotalogsinx-logsinx+a+C

Asked in: AP EAMCET 2022 (04 Jul Shift 2)

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