Mathematics › Indefinite Integration › Fundamental of Indefinite Integration
I=∫1+tanxtanx+atanxtanx+adxWe know tana=tanx+a-x=tanx+a-tanx1+tanxtanx+aSo, I=cota∫tanx+a-tanxtanx+atanxdx=cota∫1tanx-1tanx+adx=cotalogsinx-logsinx+a+C
I=∫1+tanxtanx+atanxtanx+adx
We know tana=tanx+a-x=tanx+a-tanx1+tanxtanx+a
So, I=cota∫tanx+a-tanxtanx+atanxdx
=cota∫1tanx-1tanx+adx
=cotalogsinx-logsinx+a+C
Asked in: AP EAMCET 2022 (04 Jul Shift 2)
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