18   g glucose C 6 H 12 O 6 is added to 178 . 2   g water. The vapour pressure of water (in torr) for this aqueous solution is:

Question

18 &#160; g glucose C 6 H 12 O 6 is added to 178 . 2 &#160; g water. The vapour pressure of water (in torr) for this aqueous solution is:

Aicharya · Accepted Answer

&#8710; P P o = Mole fraction of glucose. 760 - P S o l n 760 = W 1 M w t 1 W 1 M . w t 1 + w 2 M . w t 2 &#160; = 18 180 18 180 + 178.2 18 = 0.1 0.1 + 9.9 = 1 100 760 - P S o l n = 760 100 P S o l = 752.4

18   g glucose C 6 H 12 O 6 is added to 178 . 2   g water. The vapour pressure of water (in torr)…

Solution

18 &#160; g glucose C 6 H 12 O 6 is added to 178 . 2 &#160; g water. The vapour pressure of water (in torr)…

Solution

18 g glucose C 6 H 12 O 6 is added to 178 . 2 g water. The vapour pressure of water (in torr)…