15 moles of H 2 and 5.2 moles of I 2 are mixed and allowed to attain equilibrium at 500 o C . At equilibrium…

15 moles of H 2 and  5.2 moles of I 2 are mixed and allowed to attain equilibrium at 500 o C . At equilibrium, the number of moles of HI is found to be 10 mole. The equilibrium constant for the formation of HI is
  1. 50
  2. 15
  3. 100
  4. 25

Solution

H2      +       I2                  2HI

15                    5.2                           0

155      5.25                 10

Equilibrium constant

Kc=HI2H2[I2]=10×1010×0.2=50

Asked in: JEE-TOPICTESTS-CHEMISTRY

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