117.An L-C resonant circuit contains a 400 pF capacitor and an inductor of 400 μH. It is coupled to an…

117.An L-C resonant circuit contains a 400 pF capacitor and an inductor of 400 μH. It is coupled to an antenna. Wavelength of radiated electromagnetic wave is
  1. 754 m
  2. 377 m
  3. 377 cm
  4. 796 m

Solution

Given, capacitance, C = 400 pF Inductance, $L=400 \mu \mathrm{H}$ Frequency of resonating $L C$-circuit, $f=\frac{1}{2 \pi \sqrt{L C}}$ Wavelength $(\lambda)=\frac{\text { Velocity }(c)}{\text { Frequency }(f)}$ $\Rightarrow$ Wavelength, $\lambda=c \times 2 \pi \times \sqrt{L C}$ where, c is velocity of electromagnetic radiation $\begin{aligned} \lambda & =3 \times 10^8 \times 2 \times 3.14 \times \sqrt{400 \times 10^{-12} \times 400 \times 10^{-6}} \\ & =754 \mathrm{~m}\end{aligned}$

Asked in: AP EAMCET 2021 (25 Aug Shift 2)

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