100 mL of $0.1 \mathrm{M} \mathrm{Fe}^{2+}$ solution was titrated with $\frac{1}{60} \mathrm{MCr}_2…

100 mL of $0.1 \mathrm{M} \mathrm{Fe}^{2+}$ solution was titrated with $\frac{1}{60} \mathrm{MCr}_2 \mathrm{O}_7^{2-}$ solution in acid medium. What is the volume (in L ) of $\mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}$ solution consumed?
  1. 100
  2. 10
  3. 1
  4. 0.1

Solution

$\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{Fe}^{2+} \longrightarrow 2 \mathrm{Cr}^{3+}+6 \mathrm{Fe}^{3+}+7 \mathrm{H}_2 \mathrm{O}$ no. of equivalents $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7=$ no. of equivalents $\mathrm{FeSO}_4$ $\begin{aligned} & \frac{1}{60} \times \mathrm{V} \times 6=1 \times 0.1 \times 100 \\ & \mathrm{~V}_{\mathrm{ml}}=10 \times 0.1 \times 100=100 \mathrm{ml} \\ & \mathrm{~V}_{\mathrm{in} \mathrm{~L}}=\frac{100}{1000}=0.1 \mathrm{~L} \end{aligned}$

Asked in: AP EAMCET 2024 (22 May Shift 2)

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