10 . 0   ml of Na 2 CO 3 solution is titrated against 0 . 2   M   HCl solution. The following values were obtained in 5 readings. 4 . 8   ml , 4 . 9   ml , 5 . 0   ml , 5 . 0   ml and 5 . 0   ml Based on these readings, and convention of titrimetric…

Question

10 . 0 &#160; ml of Na 2 CO 3 solution is titrated against 0 . 2 &#160; M &#160; HCl solution. The following values were obtained in 5 readings. 4 . 8 &#160; ml , 4 . 9 &#160; ml , 5 . 0 &#160; ml , 5 . 0 &#160; ml and 5 . 0 &#160; ml Based on these readings, and convention of titrimetric estimation of concentration of Na 2 CO 3 solution is ___ mM . (Round off to the Nearest integer)

Aicharya · Accepted Answer

Most precise volume of HCl = 5 &#160; ml at equivalence point Meq. of Na 2 CO 3 = meq. of HCl Let molarity of Na 2 CO 3 solution = M , then M &#215; 10 &#215; 2 = 0 . 2 &#215; 5 &#215; 1 M = 0 . 05 &#160; mol / L = 0 . 05 &#215; 1000 = 50 &#160; mM

10 . 0   ml of Na 2 CO 3 solution is titrated against 0 . 2   M   HCl solution. The following…

Solution

10 . 0 &#160; ml of Na 2 CO 3 solution is titrated against 0 . 2 &#160; M &#160; HCl solution. The following…

Solution

10 . 0 ml of Na 2 CO 3 solution is titrated against 0 . 2 M HCl solution. The following…