10 . 0   mL of 0 . 05   M   KMnO 4 solution was consumed in a titration with 10 . 0   mL…

10.0 mL of 0.05 M KMnO4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is ........ ×10-2 g/L. (Round off to the nearest integer)

Solution

neqKMnO4=neqH2C2O4·2H2O

or, 10×0.051000×5=10×M1000×2

∴ Conc. of oxalic acid solution =0.125M

=0.125×126 g/L=15.75 g/L

=1575×10-2 g/L

Asked in: JEE Main 2021 (27 Jul Shift 2)

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