1 mole of equimolar mixture of Fe 2 (C 2 O 4 ) 3 and FeC 2 O 4 requires X moles of KMnO 4 in acid medium for…

1 mole of equimolar mixture of Fe 2 (C 2 O 4 ) 3 and FeC 2 O 4 requires X moles of KMnO 4 in acid medium for complete reaciton. The value of X is:
  1. 0.9
  2. 0.6
  3. 1.2
  4. 0.8

Solution

Fe 2 C 2 O 4 3 ⟶ 2 Fe 3 + + 6 CO 2 + 6 e - n Factor = 6 Fe C 2 O 4 ⟶ Fe 3 + + 2 CO 2 + 3 e - n Factor = 3

Meqs of Fe 2 (C 2 O 4 ) 3   +   Fe(C 2 O 4 )   =   0 .5   ×   6   +   0 .5   ×   3
=   4 .5   Eqs .
=   4 .5   Eqs .
of KMnO 4
=   4 .5 5   =   0 .9
moles of KMnO 4 .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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