1   L , 0 . 02 M solution of Co NH 3 5 SO 4 Br is mixed with 1   L , 0 . 02 M solution of Co NH 3…

1 L,0.02M solution of CoNH35SO4Br is mixed with 1 L,0.02M solution of CoNH35BrSO4. The resulting solution is divided into two equal parts X and treated with excess AgNO3 solution and BaCl2 solution respectively as shown below:
1 L Solution X+AgNO3 solution (excess) Y
1 L Solution X+BaCl2 solution (excess) Z
The number of moles of Y and Z respectively are
  1. 0.02,0.02
  2. 0.01,0.01
  3. 0.02,0.01
  4. 0.01,0.02

Solution

The number of moles of  CoNH35SO4Br=0.02×1=0.02 mol 

The number of moles of   CoNH35BrSO4=0.02×1=0.02 mol

The total volume of the solution becomes two Litres after mixing.

Following precipitation reactions occur:
CoNH35SO4Br+AgNO3AgBr0.01mol excess 0.01 mol

CoNH35BrSO4+BaCl2BaSO40.01mol excess 0.01 mol

Asked in: JEE Main 2023 (30 Jan Shift 2)

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