1   g of a non-volatile non-electrolyte solute is dissolved in 100   g of two different solvents A…

Elevation in Boiling point  $∆{\mathrm{T}}_{\mathrm{b}}=\mathrm{i}\times {\mathrm{k}}_{\mathrm{b}}\times \mathrm{m}$

For non-electrolyte, $\mathrm{i}=1$

m= Molar mass of solute

$$\begin{gathered} {\mathrm{m}}_1=\mathrm{molality} \mathrm{of} \mathrm{solution} 1 \\ {\mathrm{m}}_2= \mathrm{molality} \mathrm{of} \mathrm{solution} 2 \end{gathered}$$

$∆{\mathrm{T}}_{{\mathrm{b}}_1}={\mathrm{k}}_1\times 1\times {\mathrm{m}}_1,\mathrm{ }{\mathrm{m}}_1=\frac{1}{100\times \mathrm{m}}\times 1000=\frac{10}{\mathrm{m}}$

$∆{\mathrm{T}}_{{\mathrm{b}}_2}={\mathrm{k}}_2\times 1\times {\mathrm{m}}_2,\mathrm{ }{\mathrm{m}}_2=\frac{1}{100\times \mathrm{m}}\times 1000=\frac{10}{\mathrm{m}}$

${\mathrm{m}}_1={\mathrm{m}}_2$ 

$\frac{∆{\mathrm{T}}_{{\mathrm{b}}_1}}{∆{\mathrm{T}}_{{\mathrm{b}}_2}}=\frac{{\mathrm{k}}_1}{{\mathrm{k}}_2}=1:5$