1-chloro butane on treatment with alcoholic potash forms

1-chloro butane on treatment with alcoholic potash forms
  1. 2-butanol
  2. 1-butene
  3. 1-butanol
  4. 2-butene

Solution

Alc. \(\mathrm{KOH}\) is a dehydrohalogenation agent, it reacts with an alkyl halide and alkene forms as a product. Reaction of process can be given by \(\underset{\text { 1-chlorobutane }}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Cl}} \xrightarrow{\mathrm{Alc}, \mathrm{KOH}} \underset{\text { 1-butene }}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}}=\mathrm{CH}_2\) Hence, option (b) is correct.

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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