∫ 0 5 cos π x - x 2 d x , where t denotes greatest integer less than or equal to t , is equal to

05cosπx-x2dx, where t denotes greatest integer less than or equal to t, is equal to
  1. 0
  2. 2
  3. -3
  4. 4

Solution

I=05cosx2π-πxdx

x0,5 x0,52x20,1,2

I=02cos-πxdx+24cosπ-πxdx+45cos2π-πxdx

I=sinπxπ02+-sinπxπ24+sinπxπ45=0

Asked in: JEE Main 2022 (29 Jun Shift 1)

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