0.5 g of an organic compound on combustion gave 1.46 g of $\mathrm{CO}_2$ and 0.9 g of $\mathrm{H}_2…
0.5 g of an organic compound on combustion gave 1.46 g of $\mathrm{CO}_2$ and 0.9 g of $\mathrm{H}_2 \mathrm{O}$. The percentage of carbon in the compound is _______. (Nearest integer) [Given : Molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$) $\mathrm{C}: 12, \mathrm{H}: 1$, O: 16]
Solution
Organic $\rightarrow \mathrm{CO}_2$ Compound Applying POAC on ' C ' (mole) of ' C ' in compound $=\mathrm{n}_{\mathrm{CO}_2} \times 1$ So mass of ' C ' in compound $=\frac{1.46}{44} \times 12$ So, $\%$ of ' C ' in compound $=\frac{1.46}{44} \times \frac{12}{0.5} \times 100$ $=79.63$