$\int_0^{\pi / 4} \tan ^2(x) d x=$

Question

Aicharya · Accepted Answer

$\begin{aligned} I & =\int_0^{\pi / 4} \tan ^2 x d x=\int_0^{\pi / 2}\left(\sec ^2 x-1\right) d x \ & =[\tan x-x]_0^{\pi / 4}=1-\frac{\pi}{4} \end{aligned}$ Hence, option (c) is correct.

\(\int_0^{\pi / 4} \tan ^2(x) d x=\)

Solution